x^2-0.56x-0.112=0

Solution for x^2-0.56x-0.112=0 equation:

x^2-0.56x-0.112=0

a = 1; b = -0.56; c = -0.112;
Δ = b2-4ac
Δ = -0.562-4·1·(-0.112)
Δ = 0.7616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.56)-\sqrt{0.7616}}{2*1}=\frac{0.56-\sqrt{0.7616}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.56)+\sqrt{0.7616}}{2*1}=\frac{0.56+\sqrt{0.7616}}{2}
$